Credited with solving this puzzle (w/ extra credit!):
This month’s challenge is about IBM’s InterConnect 2016 conference.
Assign each letter a different digit such that the following mathematical equations would be correct (** denotes exponentiation):
a**connect = c (mod inter)
a**connect = a**toe (mod at)
a**connect = a**toe (mod cm)
n**i = banHint: By guessing a little, this can almost be entirely solved without using a computer.
For a bonus ‘*’, what is the connection of the solution to “XCF MODULE ID FILTER NOT ACCEPTED”?mod is modulo operation. I.e. x=y(mod z) means that x and y has the same remainder when divided by z. Different letters should be assigned to different digits.
Neat little puzzle-in-a-puzzle; my submission to the judges:
I believe the solution is as follows:
n=5
i=4
b=6
a=2
c=8
o=1
e=0
t=3
r=7
m=9
such that:
2^8155083 = 8 (mod 45307)
2^8155083 = 2^310 (mod 23)
2^8155083 = 2^310 (mod 89)
5^4 = 625
The IXC message for “XCF MODULE ID FILTER NOT ACCEPTED” which is IXC469I. The numeric portion is 469 which using the solution above translates to “ibm”.
